Provided by: manpages-dev_5.10-1ubuntu1_all bug

NAME

       memmove - copy memory area

SYNOPSIS

       #include <string.h>

       void *memmove(void *dest, const void *src, size_t n);

DESCRIPTION

       The  memmove()  function  copies  n bytes from memory area src to memory area dest.  The memory areas may
       overlap: copying takes place as though the bytes in src are first copied into a temporary array that does
       not overlap src or dest, and the bytes are then copied from the temporary array to dest.

RETURN VALUE

       The memmove() function returns a pointer to dest.

ATTRIBUTES

       For an explanation of the terms used in this section, see attributes(7).
       ┌───────────┬───────────────┬─────────┐
       │ InterfaceAttributeValue   │
       ├───────────┼───────────────┼─────────┤
       │ memmove() │ Thread safety │ MT-Safe │
       └───────────┴───────────────┴─────────┘

CONFORMING TO

       POSIX.1-2001, POSIX.1-2008, C89, C99, SVr4, 4.3BSD.

SEE ALSO

       bcopy(3), bstring(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)

COLOPHON

       This page is part of release 5.10 of  the  Linux  man-pages  project.   A  description  of  the  project,
       information   about   reporting   bugs,   and   the  latest  version  of  this  page,  can  be  found  at
       https://www.kernel.org/doc/man-pages/.

GNU                                                2017-03-13                                         MEMMOVE(3)